y^2+3+y=5

Solution for y^2+3+y=5 equation:

Simplifying
y2 + 3 + y = 5

Reorder the terms:
3 + y + y2 = 5

Solving
3 + y + y2 = 5

Solving for variable 'y'.

Reorder the terms:
3 + -5 + y + y2 = 5 + -5

Combine like terms: 3 + -5 = -2
-2 + y + y2 = 5 + -5

Combine like terms: 5 + -5 = 0
-2 + y + y2 = 0

Factor a trinomial.
(-2 + -1y)(1 + -1y) = 0

Subproblem 1
Set the factor '(-2 + -1y)' equal to zero and attempt to solve:

Simplifying
-2 + -1y = 0

Solving
-2 + -1y = 0

Move all terms containing y to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + -1y = 0 + 2

Combine like terms: -2 + 2 = 0
0 + -1y = 0 + 2
-1y = 0 + 2

Combine like terms: 0 + 2 = 2
-1y = 2

Divide each side by '-1'.
y = -2

Simplifying
y = -2
Subproblem 2
Set the factor '(1 + -1y)' equal to zero and attempt to solve:

Simplifying
1 + -1y = 0

Solving
1 + -1y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -1y = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1y = 0 + -1
-1y = 0 + -1

Combine like terms: 0 + -1 = -1
-1y = -1

Divide each side by '-1'.
y = 1

Simplifying
y = 1
Solution
y = {-2, 1}